2(x-4)^2-8=10

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Solution for 2(x-4)^2-8=10 equation:



2(x-4)^2-8=10
We move all terms to the left:
2(x-4)^2-8-(10)=0
We add all the numbers together, and all the variables
2(x-4)^2-18=0
We move all terms containing x to the left, all other terms to the right
2(x-4)^2=18

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